Eureka Math Grade 4 Module 5 Lesson 13 Answer Key (2024)

Engage NY Eureka Math 4th Grade Module 5 Lesson 13 Answer Key

Eureka Math Grade 4 Module 5 Lesson 13 Problem Set Answer Key

Question 1.
Place the following fractions on the number line given.
a. \(\frac{4}{3}\)

Answer:
\(\frac{4}{3}\) = 1.33.

Explanation:
In the above-given question,
given that,
plot the following points on the number line without measuring.
\(\frac{4}{3}\) = 1.33.
4/3 = 1.33.

b. \(\frac{11}{6}\)

Answer:
\(\frac{11}{6}\) = 1.83.

Explanation:
In the above-given question,
given that,
plot the following points on the number line without measuring.
\(\frac{11}{6}\) = 1.83.
11/6 = 1.83.
Eureka Math Grade 4 Module 5 Lesson 13 Answer Key (1)

c. \(\frac{17}{12}\)

Answer:
\(\frac{17}{12}\) = 1.41.

Explanation:
In the above-given question,
given that,
plot the following points on the number line without measuring.
\(\frac{17}{12}\) = 1.41.
17/12 = 1.41.

Eureka Math Grade 4 Module 5 Lesson 13 Answer Key (2)

Question 2.
Use the number line in Problem 1 to compare the fractions by writing >, ˂, or = on the lines.
a. 1\(\frac{5}{6}\) ________ 1\(\frac{5}{12}\)

Answer:
1\(\frac{5}{6}\) > 1\(\frac{5}{12}\)

Explanation:
In the above-given question,
given that,
1\(\frac{5}{6}\) = 1(5/6).
6 +5/6 = 11/6.
11/6 = 1.83
1\(\frac{5}{12}\) = 1(5/12).
12 + 5/12 = 17/12.
17/12 = 1.41.
1\(\frac{7}{12}\) > 1\(\frac{1}{2}\)

b. 1\(\frac{1}{3}\) ________ 1\(\frac{5}{12}\)

Answer:
1\(\frac{1}{3}\) <1\(\frac{5}{12}\)

Explanation:
In the above-given question,
given that,
1\(\frac{1}{3}\) = 1(1/3).
3 +1/3 = 4/3.
4/3 = 1.33
1\(\frac{5}{12}\) = 1(5/12).
12 + 5/12 = 17/12.
17/12 = 1.41.
1\(\frac{1}{3}\) < 1\(\frac{1}{2}\)

Question 3.
Place the following fractions on the number line given.
a. \(\frac{11}{8}\)

Answer:
\(\frac{11}{8}\) = 1.375.

Explanation:
In the above-given question,
given that,
plot the following points on the number line without measuring.
\(\frac{11}{8}\) = 1.375.
11/8 = 1.375.

b. \(\frac{7}{4}\)

Answer:
\(\frac{7}{4}\) = 1.75.

Explanation:
In the above-given question,
given that,
plot the following points on the number line without measuring.
\(\frac{7}{4}\) = 1.75.
7/4 = 1.75.
Eureka Math Grade 4 Module 5 Lesson 13 Answer Key (3)

c. \(\frac{15}{12}\)

Answer:
\(\frac{15}{12}\) = 1.25.

Explanation:
In the above-given question,
given that,
plot the following points on the number line without measuring.
\(\frac{15}{12}\) = 1.25.
15/12 = 1.25.

Eureka Math Grade 4 Module 5 Lesson 13 Answer Key (4)

Question 4.
Use the number line in Problem 3 to explain the reasoning you used when determining whether \(\frac{11}{8}\) or \(\frac{15}{12}\) is greater.

Question 5.
Compare the fractions given below by writing > or ˂ on the lines. Give a brief explanation for each answer referring to benchmarks.
a. \(\frac{3}{8}\) _________ \(\frac{7}{12}\)

Answer:
\(\frac{3}{8}\) < \(\frac{7}{12}\)

Explanation:
In the above-given question,
given that,
\(\frac{3}{8}\) = (3/8).
3/8 = 0.375.
\(\frac{7}{12}\) = (7/12).
7/12 = 0.583.
\(\frac{3}{8}\) < \(\frac{7}{12}\)

b. \(\frac{3}{8}\) _________ \(\frac{7}{8}\)

Answer:
\(\frac{3}{8}\) < \(\frac{7}{8}\)

Explanation:
In the above-given question,
given that,
\(\frac{3}{8}\) = (3/8).
3/8 = 0.375.
\(\frac{7}{8}\) = (7/8).
7/8 = 0.875.
\(\frac{3}{8}\) < \(\frac{7}{8}\)

c. \(\frac{8}{6}\) _________ \(\frac{11}{12}\)

Answer:
\(\frac{8}{6}\) > \(\frac{11}{12}\)

Explanation:
In the above-given question,
given that,
\(\frac{8}{6}\) = (8/6).
8/6 = 1.33.
\(\frac{11}{12}\) = (11/12).
11/12 = 0.916.
\(\frac{8}{6}\) > \(\frac{11}{12}\)

d. \(\frac{5}{12}\) _________ \(\frac{1}{3}\)

Answer:
\(\frac{5}{12}\) > \(\frac{1}{3}\)

Explanation:
In the above-given question,
given that,
\(\frac{5}{12}\) = (5/12).
5/12 = 0.416.
\(\frac{1}{3}\) = (1/3).
1/3 = 0.33.
\(\frac{5}{12}\) > \(\frac{1}{3}\)

e. \(\frac{7}{5}\) _________ \(\frac{11}{10}\)

Answer:
\(\frac{7}{5}\) > \(\frac{11}{10}\)

Explanation:
In the above-given question,
given that,
\(\frac{7}{5}\) = (7/5).
7/5 = 1.4.
\(\frac{11}{10}\) = (11/10).
11/10 = 1.1.
\(\frac{7}{5}\) > \(\frac{11}{10}\)

f. \(\frac{5}{4}\) _________ \(\frac{7}{8}\)

Answer:
\(\frac{5}{4}\) > \(\frac{7}{8}\)

Explanation:
In the above-given question,
given that,
\(\frac{5}{4}\) = (5/4).
5/4 = 1.25.
\(\frac{7}{8}\) = (7/8).
7/8 = 0.875.
\(\frac{5}{4}\) > \(\frac{7}{8}\)

g. \(\frac{13}{3}\) _________ \(\frac{9}{10}\)

Answer:
\(\frac{13}{3}\) < \(\frac{9}{10}\)

Explanation:
In the above-given question,
given that,
\(\frac{13}{3}\) = (13/3).
13/3 = 4.3.
\(\frac{9}{10}\) = (9/10).
9/10 = 0.9.
\(\frac{13}{3}\) < \(\frac{9}{10}\)

h. \(\frac{6}{8}\) _________ \(\frac{5}{4}\)

Answer:
\(\frac{6}{8}\) < \(\frac{5}{4}\)

Explanation:
In the above-given question,
given that,
\(\frac{6}{8}\) = (6/8).
6/8 = 0.75.
\(\frac{5}{4}\) = (5/4).
5/4 = 1.25.
\(\frac{6}{8}\) < \(\frac{5}{4}\)

i. \(\frac{8}{12}\) __________ \(\frac{8}{4}\)

Answer:
\(\frac{8}{12}\) < \(\frac{8}{4}\)

Explanation:
In the above-given question,
given that,
\(\frac{8}{12}\) = (8/12).
8/12 = 0.375.
\(\frac{8}{4}\) = (8/4).
8/4 = 2.
\(\frac{8}{12}\) < \(\frac{8}{4}\)

j. \(\frac{7}{5}\) __________ \(\frac{16}{10}\)

Answer:
\(\frac{7}{5}\) < \(\frac{16}{10}\)

Explanation:
In the above-given question,
given that,
\(\frac{7}{5}\) = (7/5).
7/5 = 1.4.
\(\frac{16}{10}\) = (16/10).
16/10 = 1.6.
\(\frac{7}{5}\) < \(\frac{16}{10}\)

Eureka Math Grade 4 Module 5 Lesson 13 Exit Ticket Answer Key

Question 1.
Place the following fractions on the number line given.
a. \(\frac{5}{4}\)

Answer:
\(\frac{11}{8}\) = 1.375.

Explanation:
In the above-given question,
given that,
plot the following points on the number line without measuring.
\(\frac{11}{8}\) = 1.375.
11/8 = 1.375.

b. \(\frac{10}{7}\)

Answer:
\(\frac{10}{7}\) = 1.42.

Explanation:
In the above-given question,
given that,
plot the following points on the number line without measuring.
\(\frac{10}{7}\) = 1.42.
10/7 = 1.42.
Eureka Math Grade 4 Module 5 Lesson 13 Answer Key (5)

c. \(\frac{16}{9}\)

Answer:
\(\frac{16}{9}\) = 1.77.

Explanation:
In the above-given question,
given that,
plot the following points on the number line without measuring.
\(\frac{16}{9}\) = 1.77.
16/9 = 1.77.

Eureka Math Grade 4 Module 5 Lesson 13 Answer Key (6)

Question 2.
Compare the fractions using >, ˂, or =.
a. \(\frac{5}{4}\) ________ \(\frac{10}{7}\)

Answer:
\(\frac{5}{4}\) = \(\frac{10}{7}\)

Explanation:
In the above-given question,
given that,
\(\frac{5}{4}\) = (5/4).
5/4 = 1.25.
\(\frac{10}{7}\) = (10/7).
10/7 = 1.25.
\(\frac{8}{12}\) = \(\frac{8}{4}\)

b. \(\frac{5}{4}\) ________ \(\frac{16}{9}\)

Answer:
\(\frac{5}{4}\) < \(\frac{16}{9}\)

Explanation:
In the above-given question,
given that,
\(\frac{5}{4}\) = (5/4).
5/4 = 1.25.
\(\frac{16}{9}\) = (16/9).
16/9 = 1.77.
\(\frac{5}{4}\) < \(\frac{16}{9}\)

c. \(\frac{16}{9}\) ________ \(\frac{10}{7}\)

Answer:
\(\frac{16}{9}\) < \(\frac{10}{7}\)

Explanation:
In the above-given question,
given that,
\(\frac{16}{9}\) = (16/9).
16/9 = 0.375.
\(\frac{10}{7}\) = (10/7).
10/7 = 1.42.
\(\frac{16}{9}\) < \(\frac{10}{7}\)

Eureka Math Grade 4 Module 5 Lesson 13 Homework Answer Key

Question 1.
Place the following fractions on the number line given.
a. \(\frac{3}{2}\)

Answer:
\(\frac{3}{2}\) = 1.5.

Explanation:
In the above-given question,
given that,
plot the following points on the number line without measuring.
\(\frac{3}{2}\) = 3/2.
3/2 = 1.5.

b. \(\frac{9}{5}\)

Answer:
\(\frac{9}{5}\) = 1.8.

Explanation:
In the above-given question,
given that,
plot the following points on the number line without measuring.
\(\frac{9}{5}\) = 1.8.
9/5 = 1.8.
Eureka Math Grade 4 Module 5 Lesson 13 Answer Key (7)

c. \(\frac{14}{10}\)

Answer:
\(\frac{14}{10}\) = 1.4.

Explanation:
In the above-given question,
given that,
plot the following points on the number line without measuring.
\(\frac{14}{10}\) = 1.4.
14/10 = 1.4.

Eureka Math Grade 4 Module 5 Lesson 13 Answer Key (8)

Question 2.
Use the number line in Problem 1 to compare the fractions by writing >, ˂, or = on the lines.
a. 1\(\frac{1}{6}\) ________ 1\(\frac{4}{12}\)

Answer:
1\(\frac{1}{6}\) < 1\(\frac{4}{12}\)

Explanation:
In the above-given question,
given that,
1\(\frac{1}{6}\) = 1(1/6).
6 + 1/6 = 7/6.
7/6 = 1.16.
1\(\frac{4}{12}\) = 1(4/12).
12 + 4/12 = 16/12.
16/12 = 1.33.
1\(\frac{1}{6}\) < 1\(\frac{4}{12}\)

b. 1\(\frac{1}{2}\) ________ 1\(\frac{4}{5}\)

Answer:
1\(\frac{1}{2}\) < 1\(\frac{4}{5}\)

Explanation:
In the above-given question,
given that,
1\(\frac{1}{2}\) = 1(1/2).
2 + 1/2 = 3/2.
3/2 = 1.5.
1\(\frac{4}{5}\) = 1(4/5).
5 + 4/5 = 9/5.
9/5 = 1.8.
1\(\frac{1}{2}\) < 1\(\frac{4}{5}\)

Question 3.
Place the following fractions on the number line given.
a. \(\frac{12}{9}\)

Answer:
\(\frac{12}{9}\) = 1.33.

Explanation:
In the above-given question,
given that,
plot the following points on the number line without measuring.
\(\frac{12}{9}\) = 12/9.
12/9 = 1.33.

b. \(\frac{6}{5}\)

Answer:
\(\frac{6}{5}\) = 1.2.

Explanation:
In the above-given question,
given that,
plot the following points on the number line without measuring.
\(\frac{6}{5}\) = 1.2.
6/5 = 1.2.

c. \(\frac{18}{15}\)

Answer:
\(\frac{18}{15}\) = 1.2.

Explanation:
In the above-given question,
given that,
plot the following points on the number line without measuring.
\(\frac{18}{15}\) = 1.2.
18/15 = 1.2.

Eureka Math Grade 4 Module 5 Lesson 13 Answer Key (9)

Question 4.
Use the number line in Problem 3 to explain the reasoning you used when determining whether \(\frac{12}{9}\) or \(\frac{18}{15}\) was greater.

Question 5.
Compare the fractions given below by writing > or ˂ on the lines. Give a brief explanation for each answer referring to benchmarks.
a. \(\frac{2}{5}\) _________ \(\frac{6}{8}\)

Answer:
\(\frac{2}{5}\) < \(\frac{6}{8}\)

Explanation:
In the above-given question,
given that,
\(\frac{2}{5}\) = (2/5).
2/5 = 0.4.
\(\frac{6}{8}\) = (6/8).
6/8 = 0.75.
\(\frac{2}{5}\) < \(\frac{6}{8}\)

b. \(\frac{6}{10}\) _________ \(\frac{5}{6}\)

Answer:
\(\frac{6}{10}\) < \(\frac{5}{6}\)

Explanation:
In the above-given question,
given that,
\(\frac{6}{10}\) = (6/10).
6/10 = 0.6.
\(\frac{5}{6}\) = (5/6).
5/6 = 0.83.
\(\frac{6}{10}\) < \(\frac{5}{6}\)

c. \(\frac{6}{4}\) _________ \(\frac{7}{8}\)

Answer:
\(\frac{6}{4}\) < \(\frac{7}{8}\)

Explanation:
In the above-given question,
given that,
\(\frac{6}{4}\) = (6/4).
6/4 = 0.375.
\(\frac{7}{8}\) = (7/8).
7/8 = 0.875.
\(\frac{6}{4}\) < \(\frac{7}{8}\)

d. \(\frac{1}{4}\) _________ \(\frac{8}{12}\)

Answer:
\(\frac{1}{4}\) < \(\frac{8}{12}\)

Explanation:
In the above-given question,
given that,
\(\frac{1}{4}\) = (1/4).
1/4 = 0.25.
\(\frac{8}{12}\) = (8/12).
8/12 = 0.66.
\(\frac{1}{4}\) < \(\frac{8}{12}\)

e. \(\frac{14}{12}\) _________ \(\frac{11}{6}\)

Answer:
\(\frac{14}{12}\) > \(\frac{11}{6}\)

Explanation:
In the above-given question,
given that,
\(\frac{14}{12}\) = (14/12).
14/12 = 1.16.
\(\frac{11}{6}\) = (11/6).
11/6 = 1.83.
\(\frac{14}{12}\) > \(\frac{11}{6}\)

f. \(\frac{8}{9}\) _________ \(\frac{3}{2}\)

Answer:
\(\frac{16}{9}\) < \(\frac{10}{7}\)

Explanation:
In the above-given question,
given that,
\(\frac{16}{9}\) = (16/9).
16/9 = 0.375.
\(\frac{10}{7}\) = (10/7).
10/7 = 1.42.
\(\frac{16}{9}\) < \(\frac{10}{7}\)

g. \(\frac{7}{9}\) _________ \(\frac{10}{7}\)

Answer:
\(\frac{7}{9}\) < \(\frac{10}{7}\)

Explanation:
In the above-given question,
given that,
\(\frac{7}{9}\) = (7/9).
7/9 = 0.77.
\(\frac{10}{7}\) = (10/7).
10/7 = 1.42.
\(\frac{7}{9}\) < \(\frac{10}{7}\)

h. \(\frac{3}{4}\) _________ \(\frac{4}{3}\)

Answer:
\(\frac{3}{4}\) < \(\frac{4}{3}\)

Explanation:
In the above-given question,
given that,
\(\frac{3}{4}\) = (3/4).
3/4 = 0.75.
\(\frac{4}{3}\) = (4/3).
4/3 = 1.33.
\(\frac{3}{4}\) < \(\frac{4}{3}\)

i. \(\frac{3}{8}\) _________ \(\frac{3}{2}\)

Answer:
\(\frac{3}{8}\) < \(\frac{3}{2}\)

Explanation:
In the above-given question,
given that,
\(\frac{3}{8}\) = (3/8).
3/8 = 0.375.
\(\frac{3}{2}\) = (3/2).
3/2 = 1.5.
\(\frac{3}{8}\) < \(\frac{3}{2}\)

j. \(\frac{9}{6}\) _________ \(\frac{16}{12}\)

Answer:
\(\frac{9}{6}\) > \(\frac{16}{12}\)

Explanation:
In the above-given question,
given that,
\(\frac{9}{6}\) = (9/6).
9/6 = 1.5.
\(\frac{16}{12}\) = (10/7).
16/12 = 1.33.
\(\frac{9}{6}\) > \(\frac{16}{12}\)

Eureka Math Grade 4 Module 5 Lesson 13 Answer Key (2024)

FAQs

What are the four core components of a Eureka Math TEKS lesson? ›

Lesson Components

Within every lesson, students experience the same four core components: - Fluency Practice, - Application Problem, - Concept Development (which includes a Problem Set), and - Student Debrief (which includes an Exit Ticket).

What type of math is Eureka math? ›

Eureka Math® is a holistic Prekindergarten through Grade 12 curriculum that carefully sequences mathematical progressions in expertly crafted modules, making math a joy to teach and learn. We provide in-depth professional development, learning materials, and a community of support.

What are the parts of the Eureka math lesson? ›

A typical Eureka lesson is comprised of four critical components: fluency practice, concept development (including a problem set), application problem, and student debrief (including the Exit Ticket). Each component described serves a distinct purpose.

How long should an Eureka math lesson be? ›

Not all Eureka Math lessons are formatted in the same way, but lessons in the same grade-band all follow a similar structure. Lessons in A Story of Units (PK-5) are written for a 60-minute class period, except for Pre-K lessons, which are 25 minutes, and K lessons, which are 50 minutes*.

What are the four major components of Rowland et al's knowledge quartet? ›

The 'knowledge quartet' (Rowland et al., 2009) classified these into four 'big ideas' or dimensions: foundation, transformation, connections and contingency (Figure 1).

What are core lesson planning components? ›

A successful lesson plan addresses and integrates these three key components: Objectives for student learning. Teaching/learning activities. Strategies to check student understanding.

What are the components of a guided math lesson? ›

The Guided Math Framework includes the instructional components:
  • Classroom Environment of Numeracy.
  • Math Warm-ups.
  • Whole Class Instruction.
  • Small Group Instruction.
  • Math Workshop (Centers)
  • Individual Conferences.
  • Ongoing System of Assessment.

What is Eureka Math Teks Edition? ›

Eureka Math Equip™ TEKS Edition is an adaptive diagnostic tool that identifies students' last point of success and seamlessly bridges any gaps in essential foundational knowledge through direct instructional videos, supporting lessons and fluency practice.

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